Re[z^a] == HypergeometricPFQ[{{-a}, {}, {}}, {{}, {1/2}, {1/2}}, (1/2) (1 - Re[z] + Sqrt[(1 - Re[z])^2 + Im[z]^2]), (1/2) (1 - Re[z] - Sqrt[(1 - Re[z])^2 + Im[z]^2])] /; Element[a, Reals]

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2001-10-29