ArcCsch[z] == (Pi/4) ((-Sqrt[-(1/z^2)]) z + I Sqrt[-(I/z)] Sqrt[-((I Sqrt[2] + z)/z)] Sqrt[I z] Sqrt[z/((-I) Sqrt[2] - z)] - I Sqrt[I/z] Sqrt[(I Sqrt[2] - z)/z] Sqrt[(-I) z] Sqrt[z/(I Sqrt[2] - z)] + Sqrt[-((1 + z^2)/z^2)]/ (z Sqrt[(1 + z^2)/z^4])) - (Sqrt[-z^2]/(2 z)) ArcCot[(2 + z^2)/(2 Sqrt[-z^2 - 1])]

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<mi> &#8520; </mi> <mo> &#8290; </mo> <mi> z </mi> </mrow> </msqrt> <mo> &#8290; </mo> <msqrt> <mfrac> <mi> z </mi> <mrow> <mrow> <mrow> <mo> - </mo> <mi> &#8520; </mi> </mrow> <mo> &#8290; </mo> <msqrt> <mn> 2 </mn> </msqrt> </mrow> <mo> - </mo> <mi> z </mi> </mrow> </mfrac> </msqrt> </mrow> <mo> - </mo> <mrow> <mi> &#8520; </mi> <mo> &#8290; </mo> <msqrt> <mfrac> <mi> &#8520; </mi> <mi> z </mi> </mfrac> </msqrt> <mo> &#8290; </mo> <msqrt> <mfrac> <mrow> <mrow> <mi> &#8520; </mi> <mo> &#8290; </mo> <msqrt> <mn> 2 </mn> </msqrt> </mrow> <mo> - </mo> <mi> z </mi> </mrow> <mi> z </mi> </mfrac> </msqrt> <mo> &#8290; </mo> <msqrt> <mrow> <mrow> <mo> - </mo> <mi> &#8520; </mi> </mrow> <mo> &#8290; </mo> <mi> z </mi> </mrow> </msqrt> <mo> &#8290; </mo> <msqrt> <mfrac> <mi> z </mi> <mrow> <mrow> <mi> &#8520; </mi> <mo> &#8290; </mo> <msqrt> <mn> 2 </mn> </msqrt> </mrow> <mo> - </mo> <mi> z </mi> </mrow> </mfrac> </msqrt> </mrow> <mo> + </mo> <mfrac> <msqrt> <mrow> <mo> - </mo> <mfrac> <mrow> 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2003-08-21