Integrate[Cos[d z]/(a z^2 + b z + c)^2, z] == (-((1/(b^2 - 4 a c)^(3/2)) (2 a Cos[((b - Sqrt[b^2 - 4 a c]) d)/(2 a)] - Sqrt[b^2 - 4 a c] d Sin[((b - Sqrt[b^2 - 4 a c]) d)/(2 a)]))) CosIntegral[(d (b - Sqrt[b^2 - 4 a c] + 2 a z))/(2 a)] + ((1/(b^2 - 4 a c)^(3/2)) (2 a Cos[((b + Sqrt[b^2 - 4 a c]) d)/(2 a)] + Sqrt[b^2 - 4 a c] d Sin[((b + Sqrt[b^2 - 4 a c]) d)/(2 a)])) CosIntegral[(d (b + Sqrt[b^2 - 4 a c] + 2 a z))/(2 a)] + (-((d Cos[((b + Sqrt[b^2 - 4 a c]) d)/(2 a)])/(b^2 - 4 a c)) + (2 a Sin[((b + Sqrt[b^2 - 4 a c]) d)/(2 a)])/(b^2 - 4 a c)^(3/2)) SinIntegral[(d (b + Sqrt[b^2 - 4 a c] + 2 a z))/(2 a)] + (-((d Cos[((b - Sqrt[b^2 - 4 a c]) d)/(2 a)])/(b^2 - 4 a c)) - (2 a Sin[((b - Sqrt[b^2 - 4 a c]) d)/(2 a)])/(b^2 - 4 a c)^(3/2)) SinIntegral[(d (b - Sqrt[b^2 - 4 a c] + 2 a z))/(2 a)] - ((b + 2 a z) Cos[d z])/((b^2 - 4 a c) (c + z (b + a z)))

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2002-12-18