Integrate[BesselJ[\[Nu], a Sqrt[z]] BesselI[\[Nu], b Sqrt[z]], z] == (1/(a^2 + b^2)) (2 Sqrt[z] (b BesselI[1 + \[Nu], b Sqrt[z]] BesselJ[\[Nu], a Sqrt[z]] + a BesselI[\[Nu], b Sqrt[z]] BesselJ[1 + \[Nu], a Sqrt[z]]))

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2001-10-29