(1 + z)^a == 1/(1 - (a z)/(1 + z + ((-1 + a) z)/(2 + ((-1 - a) z)/ (3 (1 + z) + ((-2 + a) z)/(2 + ((-2 - a) z)/(5 (1 + z) + ((-3 + a) z)/(2 + \[Ellipsis]))))))) /; !IntervalMemberQ[Interval[{-Infinity, -1}], z]

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2001-10-29