Integrate[((A + B Sinh[z]) Sech[z])/(a + b Cosh[z]), z] == (1/a) (2 A ArcTan[Tanh[z/2]] + (2 A b ArcTan[((a - b) Tanh[z/2])/Sqrt[-a^2 + b^2]])/Sqrt[-a^2 + b^2] + B (Log[Cosh[z]] - Log[a + b Cosh[z]]))

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2002-12-18