WeierstrassP[z, {Subscript[g, 2], Subscript[g, 3]}] == Subscript[e, i] + WeierstrassSigma[i, z, {Subscript[g, 2], Subscript[g, 3]}]^2/WeierstrassSigma[z, {Subscript[g, 2], Subscript[g, 3]}]^2 /; Element[i, {1, 2, 3}]

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2001-10-29