Hypergeometric2F1[-(5/8), 6, 19/8, z] == (1/268435456) (11 ((2048 (2239 - 4002 z + 1827 z^2))/(-1 + z)^3 - (1/z^(3/8)) (2929290 (Log[1 - z^(1/8)] + I Log[1 - I z^(1/8)] - I Log[1 + I z^(1/8)] - Log[1 + z^(1/8)] - (-1)^(1/4) Log[1 - (-1)^(1/4) z^(1/8)] + (-1)^(1/4) Log[1 + (-1)^(1/4) z^(1/8)] - (-1)^(3/4) Log[1 - (-1)^(3/4) z^(1/8)] + (-1)^(3/4) Log[1 + (-1)^(3/4) z^(1/8)])) - (1/z^(11/8)) (39585 (8 z^(3/8) + 3 Log[1 - z^(1/8)] + 3 I Log[1 - I z^(1/8)] - 3 I Log[1 + I z^(1/8)] - 3 Log[1 + z^(1/8)] - 3 (-1)^(1/4) Log[1 - (-1)^(1/4) z^(1/8)] + 3 (-1)^(1/4) Log[1 + (-1)^(1/4) z^(1/8)] - 3 (-1)^(3/4) Log[1 - (-1)^(3/4) z^(1/8)] + 3 (-1)^(3/4) Log[1 + (-1)^(3/4) z^(1/8)])) - 13181805 (-(8/5) + z^(5/8) (-Log[1 - z^(1/8)] - I Log[1 - I z^(1/8)] + I Log[1 + I z^(1/8)] + Log[1 + z^(1/8)] + (-1)^(1/4) Log[1 - (-1)^(1/4) z^(1/8)] - (-1)^(1/4) Log[1 + (-1)^(1/4) z^(1/8)] + (-1)^(3/4) Log[1 - (-1)^(3/4) z^(1/8)] - (-1)^(3/4) Log[1 + (-1)^(3/4) z^(1/8)]))))

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</apply> </apply> <cn type='integer'> 1 </cn> </apply> </apply> </apply> <apply> <ln /> <apply> <plus /> <apply> <power /> <ci> z </ci> <cn type='rational'> 1 <sep /> 8 </cn> </apply> <cn type='integer'> 1 </cn> </apply> </apply> <apply> <times /> <apply> <power /> <cn type='integer'> -1 </cn> <cn type='rational'> 1 <sep /> 4 </cn> </apply> <apply> <ln /> <apply> <plus /> <cn type='integer'> 1 </cn> <apply> <times /> <cn type='integer'> -1 </cn> <apply> <times /> <apply> <power /> <cn type='integer'> -1 </cn> <cn type='rational'> 1 <sep /> 4 </cn> </apply> <apply> <power /> <ci> z </ci> <cn type='rational'> 1 <sep /> 8 </cn> </apply> </apply> </apply> </apply> </apply> </apply> <apply> <times /> <cn type='integer'> -1 </cn> <apply> <times /> <apply> <power /> <cn type='integer'> -1 </cn> <cn type='rational'> 1 <sep /> 4 </cn> </apply> <apply> <ln /> <apply> <plus /> <apply> <times /> <apply> <power /> <cn type='integer'> -1 </cn> <cn type='rational'> 1 <sep /> 4 </cn> </apply> <apply> 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2007-05-02