LegendreQ[5, 5, 3, z] == (1/(2 (z - 1)^(5/2) (z + 1)^(5/2))) (3 (-2 z (965 + 3 z^2 (-790 + 896 z^2 - 490 z^4 + 105 z^6)) + 315 (-1 + z^2)^5 (Log[z + 1] - Log[z - 1])))

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2001-10-29