Wronskian[s^z MathieuS[a, q, b r^z], s^z MathieuC[a, q, b r^z], z] == b r^z s^(2 z) Log[r] (MathieuCPrime[a, q, 0] MathieuS[a, q, 0] - MathieuC[a, q, 0] MathieuSPrime[a, q, 0])

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2007-05-02