DivisorSum[Subscript[d, j]^\[Mu] DivisorSigma[\[Mu], Subscript[d, j]], {Subscript[d, j], n}] == DivisorSum[(n/Subscript[d, j])^(2 \[Mu]) DivisorSigma[\[Mu], Subscript[d, j]], {Subscript[d, j], n}] /; Element[Subscript[d, j], Divisors[n]] && Element[\[Mu], Integers]

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2001-10-29