StruveL[\[Nu], z] - (z/Sqrt[z^2]) BesselI[\[Nu], z] \[Proportional] (-((2^(1 - \[Nu]) z^(\[Nu] - 1))/(Sqrt[Pi] Gamma[1/2 + \[Nu]]))) (1 + O[1/z^(2 n + 2)]) /; Abs[Arg[z]] != Pi/2 && (Abs[z] -> Infinity)

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2007-05-02