a ArcCoth[x] + b ArcSech[y] == I a Pi Floor[(-Arg[1 - 1/x] + Arg[1 + 1/x] + Pi)/(2 Pi)] - 2 I Pi (Floor[(-Arg[((x - 1)/(x + 1))^(-(a/2))] - Arg[(Sqrt[1/y - 1] Sqrt[1 + 1/y] + 1/y)^b] + Pi)/(2 Pi)] + Floor[((1/2) Im[a Log[(x - 1)/(x + 1)]] + Pi)/(2 Pi)] + Floor[(Pi - Im[b Log[Sqrt[1/y - 1] Sqrt[1 + 1/y] + 1/y]])/(2 Pi)]) + Log[(Sqrt[1/y - 1] Sqrt[1 + 1/y] + 1/y)^b/((x - 1)/(x + 1))^(a/2)]

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2007-05-02