a ArcSec[x] + b ArcTanh[y] == (Pi a)/2 - 2 I Pi (Floor[(-Arg[(Sqrt[1 - 1/x^2] + I/x)^(I a)/(1 - y)^(b/2)] - Arg[(y + 1)^(b/2)] + Pi)/(2 Pi)] + Floor[(Pi - Im[Log[(Sqrt[1 - 1/x^2] + I/x)^(I a)/(1 - y)^(b/2)]])/ (2 Pi)] + Floor[(Pi - (1/2) Im[b Log[y + 1]])/(2 Pi)]) - 2 I Pi (Floor[(-Arg[(Sqrt[1 - 1/x^2] + I/x)^(I a)] - Arg[(1 - y)^(-(b/2))] + Pi)/(2 Pi)] + Floor[((1/2) Im[b Log[1 - y]] + Pi)/(2 Pi)] + Floor[(Pi - Re[a Log[Sqrt[1 - 1/x^2] + I/x]])/(2 Pi)]) + I (1 - (-1)^(Floor[-(Arg[((y + 1)^(b/2) (Sqrt[1 - 1/x^2] + I/x)^(I a))/ (1 - y)^(b/2) + 1]/(2 Pi))] - Floor[-(Arg[((Sqrt[1 - 1/x^2] + I/x)^(I a) (y + 1)^(b/2))/ (1 - y)^(b/2)]/(2 Pi))])) Pi - I (-1)^(Floor[-(Arg[((Sqrt[1 - 1/x^2] + I/x)^(I a) (y + 1)^(b/2))/ (1 - y)^(b/2)]/Pi)] + Floor[Arg[((Sqrt[1 - 1/x^2] + I/x)^(I a) (y + 1)^(b/2))/(1 - y)^(b/2) - 1]/(2 Pi) - Arg[((y + 1)^(b/2) (Sqrt[1 - 1/x^2] + I/x)^(I a))/ (1 - y)^(b/2) + 1]/(2 Pi) + 1/2]) ArcSec[(2 (Sqrt[1 - 1/x^2] + I/x)^(I a) (y + 1)^(b/2))/ ((1 - y)^(b/2) (((y + 1)^b (Sqrt[1 - 1/x^2] + I/x)^(2 I a))/(1 - y)^b + 1))]

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