D[ArcTan[z], {z, \[Alpha]}] == 2^(\[Alpha] - 1) Sqrt[Pi] z^(1 - \[Alpha]) HypergeometricPFQRegularized[{1/2, 1, 1}, {1 - \[Alpha]/2, 3/2 - \[Alpha]/2}, -z^2]

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2001-10-29