InverseJacobiDN[z, m] == (1/Sqrt[m - 1]) EllipticK[1/(1 - m)] - ((z Sqrt[1 - z^2])/Sqrt[z^2 - 1]) HypergeometricPFQ[{{1}, {1/2}, {1/2}}, {{}, {3/2}, {}}, z^2, m]

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2001-10-29