WeierstrassSigma[i, z, {Subscript[g, 2], Subscript[g, 3]}]^2 - WeierstrassSigma[j, z, {Subscript[g, 2], Subscript[g, 3]}]^2 == (Subscript[e, j] - Subscript[e, i]) WeierstrassSigma[z, {Subscript[g, 2], Subscript[g, 3]}]^2 /; Element[{i, j}, {1, 2, 3}] && i != j

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2001-10-29