Derivative[1, 0, 0][WhittakerM][\[Nu], \[Mu], z] == ((-(1/(2 \[Mu] + 1))) z^(3/2 + \[Mu]) HypergeometricPFQ[ {{\[Mu] - \[Nu] + 3/2}, {1}, {1, \[Mu] - \[Nu] + 1/2}}, {{2, 2 \[Mu] + 2}, {}, {\[Mu] - \[Nu] + 3/2}}, z, z])/E^(z/2)

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2007-05-02