WhittakerM[\[Nu], \[Mu], z] == (z^(\[Mu] + 1/2) HypergeometricPFQ[{Subscript[a, 1], \[Ellipsis], Subscript[a, p]}, {Subscript[b, 1], \[Ellipsis], Subscript[b, q]}, z])/ E^(z/2) /; p == 1 && q == 1 && Subscript[a, 1] == \[Mu] - \[Nu] + 1/2 && Subscript[b, 1] == 2 \[Mu] + 1

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2007-05-02