Integrate[((A + B Sinh[z]) Tanh[z])/(a + b Sinh[z]), z] == (1/(b (a^2 + b^2))) (2 b (A b - a B) ArcTan[Tanh[z/2]] + b (a A + b B) Log[Cosh[z]] + a ((-A) b + a B) Log[a + b Sinh[z]])

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2002-12-18